9=n/2(n-3)

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Solution for 9=n/2(n-3) equation: 



9=n/2(n-3)

We move all terms to the left:

9-(n/2(n-3))=0



Domain of the equation: 2(n-3))!=0

n∈R



We multiply all the terms by the denominator


-(n+9*2(n-3))=0



We calculate terms in parentheses: -(n+9*2(n-3)), so:

n+9*2(n-3)

Wy multiply elements

n+18n(n

Back to the equation:

-(n+18n(n)

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