9=7/3(3)+b

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Solution for 9=7/3(3)+b equation:



9=7/3(3)+b
We move all terms to the left:
9-(7/3(3)+b)=0
Domain of the equation: 33+b)!=0
We move all terms containing b to the left, all other terms to the right
b)!=-33
b!=-33/1
b!=-33
b∈R
We add all the numbers together, and all the variables
-(+b+7/33)+9=0
We get rid of parentheses
-b+9-7/33=0
We multiply all the terms by the denominator
-b*33-7+9*33=0
We add all the numbers together, and all the variables
-b*33+290=0
Wy multiply elements
-33b+290=0
We move all terms containing b to the left, all other terms to the right
-33b=-290
b=-290/-33
b=8+26/33

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