9=3(c+12)

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Solution for 9=3(c+12) equation: 



9=3(c+12)

We move all terms to the left:

9-(3(c+12))=0



We calculate terms in parentheses: -(3(c+12)), so:

3(c+12)

We multiply parentheses

3c+36

Back to the equation:

-(3c+36)



We get rid of parentheses

-3c-36+9=0

We add all the numbers together, and all the variables

-3c-27=0

We move all terms containing c to the left, all other terms to the right

-3c=27

c=27/-3

c=-9

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