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9=2/3(3x+4)
We move all terms to the left:
9-(2/3(3x+4))=0
Domain of the equation: 3(3x+4))!=0We multiply all the terms by the denominator
x∈R
-(2+9*3(3x+4))=0
We calculate terms in parentheses: -(2+9*3(3x+4)), so:We add all the numbers together, and all the variables
2+9*3(3x+4)
determiningTheFunctionDomain 9*3(3x+4)+2
Wy multiply elements
27x(3+2
Back to the equation:
-(27x(3+2)
-(27x5=0
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