9=2(n+3)+1

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Solution for 9=2(n+3)+1 equation: 



9=2(n+3)+1

We move all terms to the left:

9-(2(n+3)+1)=0



We calculate terms in parentheses: -(2(n+3)+1), so:

2(n+3)+1

We multiply parentheses

2n+6+1

We add all the numbers together, and all the variables

2n+7

Back to the equation:

-(2n+7)



We get rid of parentheses

-2n-7+9=0

We add all the numbers together, and all the variables

-2n+2=0

We move all terms containing n to the left, all other terms to the right

-2n=-2

n=-2/-2

n=1

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