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9=1/2(5t+6)
We move all terms to the left:
9-(1/2(5t+6))=0
Domain of the equation: 2(5t+6))!=0We multiply all the terms by the denominator
t∈R
-(1+9*2(5t+6))=0
We calculate terms in parentheses: -(1+9*2(5t+6)), so:We add all the numbers together, and all the variables
1+9*2(5t+6)
determiningTheFunctionDomain 9*2(5t+6)+1
Wy multiply elements
18t(5+1
Back to the equation:
-(18t(5+1)
-(18t6=0
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