9=(c-4)/3

Solution for 9=(c-4)/3 equation:

9=(c-4)/3

We move all terms to the left:

9-((c-4)/3)=0

We multiply all the terms by the denominator


-((c-4)+9*3)=0


We calculate terms in parentheses: -((c-4)+9*3), so:

(c-4)+9*3

We add all the numbers together, and all the variables

(c-4)+27

We get rid of parentheses

c-4+27

We add all the numbers together, and all the variables

c+23

Back to the equation:

-(c+23)


We get rid of parentheses

-c-23=0

We add all the numbers together, and all the variables

-1c-23=0

We move all terms containing c to the left, all other terms to the right

-c=23

c=23/-1

c=-23