99-2(3x-8)=3x+10

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Solution for 99-2(3x-8)=3x+10 equation: 



99-2(3x-8)=3x+10

We move all terms to the left:

99-2(3x-8)-(3x+10)=0

We multiply parentheses

-6x-(3x+10)+16+99=0

We get rid of parentheses

-6x-3x-10+16+99=0

We add all the numbers together, and all the variables

-9x+105=0

We move all terms containing x to the left, all other terms to the right

-9x=-105

x=-105/-9

x=11+2/3

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