960=x2+10x

Solution for 960=x2+10x equation:

960=x2+10x

We move all terms to the left:

960-(x2+10x)=0

We add all the numbers together, and all the variables

-(+x^2+10x)+960=0

We get rid of parentheses

-x^2-10x+960=0

We add all the numbers together, and all the variables

-1x^2-10x+960=0

a = -1; b = -10; c = +960;
Δ = b2-4ac
Δ = -102-4·(-1)·960
Δ = 3940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3940}=\sqrt{4*985}=\sqrt{4}*\sqrt{985}=2\sqrt{985}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{985}}{2*-1}=\frac{10-2\sqrt{985}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{985}}{2*-1}=\frac{10+2\sqrt{985}}{-2}
$