96+2x=(80+3x)2

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Solution for 96+2x=(80+3x)2 equation: 



96+2x=(80+3x)2

We move all terms to the left:

96+2x-((80+3x)2)=0

We add all the numbers together, and all the variables

2x-((3x+80)2)+96=0



We calculate terms in parentheses: -((3x+80)2), so:

(3x+80)2

We multiply parentheses

6x+160

Back to the equation:

-(6x+160)



We get rid of parentheses

2x-6x-160+96=0

We add all the numbers together, and all the variables

-4x-64=0

We move all terms containing x to the left, all other terms to the right

-4x=64

x=64/-4

x=-16

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