936=2x2+8

Solution for 936=2x2+8 equation:

936=2x^2+8

We move all terms to the left:

936-(2x^2+8)=0

We get rid of parentheses

-2x^2-8+936=0

We add all the numbers together, and all the variables

-2x^2+928=0

a = -2; b = 0; c = +928;
Δ = b2-4ac
Δ = 02-4·(-2)·928
Δ = 7424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7424}=\sqrt{256*29}=\sqrt{256}*\sqrt{29}=16\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{29}}{2*-2}=\frac{0-16\sqrt{29}}{-4}
=-\frac{16\sqrt{29}}{-4}
=-\frac{4\sqrt{29}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{29}}{2*-2}=\frac{0+16\sqrt{29}}{-4}
=\frac{16\sqrt{29}}{-4}
=\frac{4\sqrt{29}}{-1}
$