936=(x+6)(2x-4)

Solution for 936=(x+6)(2x-4) equation:

936=(x+6)(2x-4)

We move all terms to the left:

936-((x+6)(2x-4))=0

We multiply parentheses ..

-((+2x^2-4x+12x-24))+936=0


We calculate terms in parentheses: -((+2x^2-4x+12x-24)), so:

(+2x^2-4x+12x-24)

We get rid of parentheses

2x^2-4x+12x-24

We add all the numbers together, and all the variables

2x^2+8x-24

Back to the equation:

-(2x^2+8x-24)


We get rid of parentheses

-2x^2-8x+24+936=0

We add all the numbers together, and all the variables

-2x^2-8x+960=0

a = -2; b = -8; c = +960;
Δ = b2-4ac
Δ = -82-4·(-2)·960
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-88}{2*-2}=\frac{-80}{-4}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+88}{2*-2}=\frac{96}{-4}
=-24
$