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90=8x+x2
We move all terms to the left:
90-(8x+x2)=0
We add all the numbers together, and all the variables
-(+8x+x^2)+90=0
We get rid of parentheses
-x^2-8x+90=0
We add all the numbers together, and all the variables
-1x^2-8x+90=0
a = -1; b = -8; c = +90;
Δ = b2-4ac
Δ = -82-4·(-1)·90
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{106}}{2*-1}=\frac{8-2\sqrt{106}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{106}}{2*-1}=\frac{8+2\sqrt{106}}{-2} $
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