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90=2x(x-4)
We move all terms to the left:
90-(2x(x-4))=0
We calculate terms in parentheses: -(2x(x-4)), so:We get rid of parentheses
2x(x-4)
We multiply parentheses
2x^2-8x
Back to the equation:
-(2x^2-8x)
-2x^2+8x+90=0
a = -2; b = 8; c = +90;
Δ = b2-4ac
Δ = 82-4·(-2)·90
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-28}{2*-2}=\frac{-36}{-4} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+28}{2*-2}=\frac{20}{-4} =-5 $
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