90=(4+2x)+(9x-2)

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Solution for 90=(4+2x)+(9x-2) equation: 



90=(4+2x)+(9x-2)

We move all terms to the left:

90-((4+2x)+(9x-2))=0

We add all the numbers together, and all the variables

-((2x+4)+(9x-2))+90=0



We calculate terms in parentheses: -((2x+4)+(9x-2)), so:

(2x+4)+(9x-2)

We get rid of parentheses

2x+9x+4-2

We add all the numbers together, and all the variables

11x+2

Back to the equation:

-(11x+2)



We get rid of parentheses

-11x-2+90=0

We add all the numbers together, and all the variables

-11x+88=0

We move all terms containing x to the left, all other terms to the right

-11x=-88

x=-88/-11

x=+8

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