90/x-90/(x-5)=1/5

Solution for 90/x-90/(x-5)=1/5 equation:

90/x-90/(x-5)=1/5

We move all terms to the left:

90/x-90/(x-5)-(1/5)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: (x-5)!=0

We move all terms containing x to the left, all other terms to the right

x!=5

x∈R


We add all the numbers together, and all the variables

90/x-90/(x-5)-(+1/5)=0

We get rid of parentheses

90/x-90/(x-5)-1/5=0

We calculate fractions


(-1x^2*()/(5x^2-25x)+(450x-2250)/(5x^2-25x)+(-2250x)/(5x^2-25x)=0


We calculate terms in parentheses: +(-1x^2*()/(5x^2-25x)+(450x-2250)/(5x^2-25x)+(-2250x)/(5x^2-25x), so:

-1x^2*()/(5x^2-25x)+(450x-2250)/(5x^2-25x)+(-2250x)/(5x^2-25x

We calculate fractions


(-1x^2*()+(450x-2250)*(5x^2-25x)/((5x^2-25x)*(5x^2-25x)+((-2250x)*(5x^2-25x))/((5x^2-25x)*(5x^2-25x)


We calculate terms in parentheses: +(-1x^2*()+(450x-2250)*(5x^2-25x)/((5x^2-25x)*(5x^2-25x)+((-2250x)*(5x^2-25x))/((5x^2-25x)*(5x^2-25x), so:

-1x^2*()+(450x-2250)*(5x^2-25x)/((5x^2-25x)*(5x^2-25x)+((-2250x)*(5x^2-25x))/((5x^2-25x)*(5x^2-25x

We can not solve this equation