90+3/2b+b(b+45)(2b-90)=540

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Solution for 90+3/2b+b(b+45)(2b-90)=540 equation: 



90+3/2b+b(b+45)(2b-90)=540

We move all terms to the left:

90+3/2b+b(b+45)(2b-90)-(540)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

3/2b+b(b+45)(2b-90)-450=0

We multiply parentheses ..

b(+2b^2-90b+90b-4050)+3/2b-450=0

We multiply all the terms by the denominator


(b(+2b^2-90b+90b-4050))*2b-450*2b+3=0

Wy multiply elements

(b(+2b^2-90b+90b-4050))*2b-900b+3=0

We move all terms containing b to the left, all other terms to the right

(b(+2b^2-90b+90b-4050))*2b-900b=-3

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