90+2x=3x(x-7)

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Solution for 90+2x=3x(x-7) equation:



90+2x=3x(x-7)
We move all terms to the left:
90+2x-(3x(x-7))=0
We calculate terms in parentheses: -(3x(x-7)), so:
3x(x-7)
We multiply parentheses
3x^2-21x
Back to the equation:
-(3x^2-21x)
We get rid of parentheses
-3x^2+2x+21x+90=0
We add all the numbers together, and all the variables
-3x^2+23x+90=0
a = -3; b = 23; c = +90;
Δ = b2-4ac
Δ = 232-4·(-3)·90
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1609}}{2*-3}=\frac{-23-\sqrt{1609}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1609}}{2*-3}=\frac{-23+\sqrt{1609}}{-6} $

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