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90(3x+2)x=1
We move all terms to the left:
90(3x+2)x-(1)=0
We multiply parentheses
270x^2+180x-1=0
a = 270; b = 180; c = -1;
Δ = b2-4ac
Δ = 1802-4·270·(-1)
Δ = 33480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{33480}=\sqrt{36*930}=\sqrt{36}*\sqrt{930}=6\sqrt{930}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-6\sqrt{930}}{2*270}=\frac{-180-6\sqrt{930}}{540} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+6\sqrt{930}}{2*270}=\frac{-180+6\sqrt{930}}{540} $
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