9/x+1-5/2=8/3x+3

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Solution for 9/x+1-5/2=8/3x+3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

9/x-(5/2)+1 = (8/3)*x+3 // - (8/3)*x+3

9/x-((8/3)*x)-(5/2)-3+1 = 0

(-8/3)*x+9/x-5/2-3+1 = 0

9*x^-1-8/3*x^1-9/2*x^0 = 0

(9*x^0-8/3*x^2-9/2*x^1)/(x^1) = 0 // * x^2

x^1*(9*x^0-8/3*x^2-9/2*x^1) = 0

x^1

(-8/3)*x^2+(-9/2)*x+9 = 0

(-8/3)*x^2+(-9/2)*x+9 = 0

DELTA = (-9/2)^2-(4*9*(-8/3))

DELTA = 465/4

DELTA > 0

x = ((465/4)^(1/2)-(-9/2))/(2*(-8/3)) or x = (-(-9/2)-(465/4)^(1/2))/(2*(-8/3))

x = -3/16*((465/4)^(1/2)+9/2) or x = -3/16*(9/2-(465/4)^(1/2))

x in { -3/16*((465/4)^(1/2)+9/2), -3/16*(9/2-(465/4)^(1/2))}

x in { -3/16*((465/4)^(1/2)+9/2), -3/16*(9/2-(465/4)^(1/2)) }

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