If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(9/7)*(x/6-2) = 0
9/7*(1/6*x-2) = 0
( 1/6*x-2 )
1/6*x-2 = 0 // + 2
1/6*x = 2 // : 1/6
x = 2/1/6
x = 12
( 9/7 )
9/7 = 0
x belongs to the empty set
x = 12
| f(-x)=x^2+9x+8 | | (13b-2)-6(2b+3)=-2 | | 25–z/8=12.5 | | 32/3(6) | | x^2+10r+14=-7 | | 4x^2+16r=65 | | x-x(.2)=15000 | | x(x-8)=15 | | 7(15)=6(x+6) | | -5/2-7 | | -7/8k=-12 | | 2/3x-5/2=7 | | .6/.0024 | | -1/3p=3 | | 5(14)=7x | | 9v=7v-10 | | -128=2+10n | | 2x+1=O | | v=3t^4+t^2 | | G-(-7)=12 | | 12y-27y+108=78 | | G-(-7)= | | 6/x=8/24 | | 4=2x+11-x | | (A^2/-3b^4)3 | | x^2(x^3-2x^2+4)=0 | | 3-m/7=14 | | x^2(x^3-2x^2-4)=0 | | 20x-36=90 | | x^2(x^3-2x^2-4x)=0 | | 2(5x+4)=7x-10 | | 2(5x-4)=7x-10 |