9/5+3/5x=27/10+7/2x+1/2

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Solution for 9/5+3/5x=27/10+7/2x+1/2 equation: 


x in (-oo:+oo)

(3/5)*x+9/5 = (7/2)*x+27/10+1/2 // - (7/2)*x+27/10+1/2

(3/5)*x-((7/2)*x)+9/5-(27/10)-(1/2) = 0

(3/5)*x+(-7/2)*x+9/5-27/10-1/2 = 0

-29/10*x-7/5 = 0 // + 7/5

-29/10*x = 7/5 // : -29/10

x = 7/5/(-29/10)

x = -14/29

x = -14/29

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