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9/4x-1=3x
We move all terms to the left:
9/4x-1-(3x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-3x+9/4x-1=0
We multiply all the terms by the denominator
-3x*4x-1*4x+9=0
Wy multiply elements
-12x^2-4x+9=0
a = -12; b = -4; c = +9;
Δ = b2-4ac
Δ = -42-4·(-12)·9
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{7}}{2*-12}=\frac{4-8\sqrt{7}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{7}}{2*-12}=\frac{4+8\sqrt{7}}{-24} $
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