9/49=n2

Solution for 9/49=n2 equation:

9/49=n2

We move all terms to the left:

9/49-(n2)=0

We add all the numbers together, and all the variables

-1n^2+9/49=0

We multiply all the terms by the denominator


-1n^2*49+9=0

Wy multiply elements

-49n^2+9=0

a = -49; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-49)·9
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*-49}=\frac{-42}{-98}
=3/7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*-49}=\frac{42}{-98}
=-3/7
$