9/4-3/p=4p+3/4p

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Solution for 9/4-3/p=4p+3/4p equation: 


D( p )

p = 0

p = 0

p = 0

p in (-oo:0) U (0:+oo)

9/4-(3/p) = 4*p+(3/4)*p // - 4*p+(3/4)*p

9/4-(4*p)-((3/4)*p)-(3/p) = 0

(-3/4)*p-4*p-3*p^-1+9/4 = 0

9/4*p^0-19/4*p^1-3*p^-1 = 0

(9/4*p^1-19/4*p^2-3*p^0)/(p^1) = 0 // * p^2

p^1*(9/4*p^1-19/4*p^2-3*p^0) = 0

p^1

(-19/4)*p^2+(9/4)*p-3 = 0

(-19/4)*p^2+(9/4)*p-3 = 0

DELTA = (9/4)^2-(-3*4*(-19/4))

DELTA = -831/16

DELTA < 0

p in { } 

p belongs to the empty set

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