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9/3(3-x)=3/4(x-3)
We move all terms to the left:
9/3(3-x)-(3/4(x-3))=0
Domain of the equation: 3(3-x)!=0
x∈R
Domain of the equation: 4(x-3))!=0We add all the numbers together, and all the variables
x∈R
9/3(-1x+3)-(3/4(x-3))=0
We calculate fractions
(36xx/(3(-1x+3)*4(x-3)))+(-9x0/(3(-1x+3)*4(x-3)))=0
We calculate terms in parentheses: +(36xx/(3(-1x+3)*4(x-3))), so:
36xx/(3(-1x+3)*4(x-3))
We multiply all the terms by the denominator
36xx
Back to the equation:
+(36xx)
We calculate terms in parentheses: +(-9x0/(3(-1x+3)*4(x-3))), so:We get rid of parentheses
-9x0/(3(-1x+3)*4(x-3))
We multiply all the terms by the denominator
-9x0
We add all the numbers together, and all the variables
-9x
Back to the equation:
+(-9x)
36xx-9x=0
We add all the numbers together, and all the variables
-9x+36xx=0
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