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9/2x=51/10x-30
We move all terms to the left:
9/2x-(51/10x-30)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 10x-30)!=0We get rid of parentheses
x∈R
9/2x-51/10x+30=0
We calculate fractions
90x/20x^2+(-102x)/20x^2+30=0
We multiply all the terms by the denominator
90x+(-102x)+30*20x^2=0
Wy multiply elements
600x^2+90x+(-102x)=0
We get rid of parentheses
600x^2+90x-102x=0
We add all the numbers together, and all the variables
600x^2-12x=0
a = 600; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·600·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*600}=\frac{0}{1200} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*600}=\frac{24}{1200} =1/50 $
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