9/14c+1/7c=2/3

Solution for 9/14c+1/7c=2/3 equation:

9/14c+1/7c=2/3

We move all terms to the left:

9/14c+1/7c-(2/3)=0


Domain of the equation: 14c!=0

c!=0/14

c!=0

c∈R



Domain of the equation: 7c!=0

c!=0/7

c!=0

c∈R


We add all the numbers together, and all the variables

9/14c+1/7c-(+2/3)=0

We get rid of parentheses

9/14c+1/7c-2/3=0

We calculate fractions


(-1372c^2)/882c^2+567c/882c^2+126c/882c^2=0

We multiply all the terms by the denominator


(-1372c^2)+567c+126c=0

We add all the numbers together, and all the variables

(-1372c^2)+693c=0

We get rid of parentheses

-1372c^2+693c=0

a = -1372; b = 693; c = 0;
Δ = b2-4ac
Δ = 6932-4·(-1372)·0
Δ = 480249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{480249}=693$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(693)-693}{2*-1372}=\frac{-1386}{-2744}
=99/196
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(693)+693}{2*-1372}=\frac{0}{-2744}
=0
$