9/(p-15)=(3p-12)/(p-15)-3/p

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Solution for 9/(p-15)=(3p-12)/(p-15)-3/p equation:


D( p )

p = 0

p-15 = 0

p = 0

p = 0

p-15 = 0

p-15 = 0

p-15 = 0 // + 15

p = 15

p in (-oo:0) U (0:15) U (15:+oo)

9/(p-15) = (3*p-12)/(p-15)-(3/p) // - (3*p-12)/(p-15)-(3/p)

9/(p-15)-((3*p-12)/(p-15))+3/p = 0

9/(p-15)+(-1*(3*p-12))/(p-15)+3/p = 0

(9*p)/(p*(p-15))+(-1*p*(3*p-12))/(p*(p-15))+(3*(p-15))/(p*(p-15)) = 0

3*(p-15)-1*p*(3*p-12)+9*p = 0

21*p-3*p^2+3*p-45 = 0

24*p-3*p^2-45 = 0

24*p-3*p^2-45 = 0

3*(8*p-p^2-15) = 0

8*p-p^2-15 = 0

DELTA = 8^2-(-15*(-1)*4)

DELTA = 4

DELTA > 0

p = (4^(1/2)-8)/(-1*2) or p = (-4^(1/2)-8)/(-1*2)

p = 3 or p = 5

3*(p-3)*(p-5) = 0

(3*(p-3)*(p-5))/(p*(p-15)) = 0

(3*(p-3)*(p-5))/(p*(p-15)) = 0 // * p*(p-15)

3*(p-3)*(p-5) = 0

( 3 )

3 = 0

p belongs to the empty set

( p-3 )

p-3 = 0 // + 3

p = 3

( p-5 )

p-5 = 0 // + 5

p = 5

p in { 3, 5 }

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