9/(a+3)=4/(a+2)

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Solution for 9/(a+3)=4/(a+2) equation:


D( a )

a+2 = 0

a+3 = 0

a+2 = 0

a+2 = 0

a+2 = 0 // - 2

a = -2

a+3 = 0

a+3 = 0

a+3 = 0 // - 3

a = -3

a in (-oo:-3) U (-3:-2) U (-2:+oo)

9/(a+3) = 4/(a+2) // - 4/(a+2)

9/(a+3)-(4/(a+2)) = 0

9/(a+3)-4*(a+2)^-1 = 0

9/(a+3)-4/(a+2) = 0

(9*(a+2))/((a+3)*(a+2))+(-4*(a+3))/((a+3)*(a+2)) = 0

9*(a+2)-4*(a+3) = 0

5*a+6 = 0

(5*a+6)/((a+3)*(a+2)) = 0

(5*a+6)/((a+3)*(a+2)) = 0 // * (a+3)*(a+2)

5*a+6 = 0

5*a+6 = 0 // - 6

5*a = -6 // : 5

a = -6/5

a = -6/5

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