9-5c=12-(6c+7)

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Solution for 9-5c=12-(6c+7) equation: 



9-5c=12-(6c+7)

We move all terms to the left:

9-5c-(12-(6c+7))=0



We calculate terms in parentheses: -(12-(6c+7)), so:

12-(6c+7)

determiningTheFunctionDomain
-(6c+7)+12

We get rid of parentheses

-6c-7+12

We add all the numbers together, and all the variables

-6c+5

Back to the equation:

-(-6c+5)



We get rid of parentheses

-5c+6c-5+9=0

We add all the numbers together, and all the variables

c+4=0

We move all terms containing c to the left, all other terms to the right

c=-4

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