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9-5=4+2(x+3)
We move all terms to the left:
9-5-(4+2(x+3))=0
We add all the numbers together, and all the variables
-(4+2(x+3))+4=0
We calculate terms in parentheses: -(4+2(x+3)), so:We get rid of parentheses
4+2(x+3)
determiningTheFunctionDomain 2(x+3)+4
We multiply parentheses
2x+6+4
We add all the numbers together, and all the variables
2x+10
Back to the equation:
-(2x+10)
-2x-10+4=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3
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