9-52=12-(6z+7)

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Solution for 9-52=12-(6z+7) equation: 



9-52=12-(6z+7)

We move all terms to the left:

9-52-(12-(6z+7))=0

We add all the numbers together, and all the variables

-(12-(6z+7))-43=0



We calculate terms in parentheses: -(12-(6z+7)), so:

12-(6z+7)

determiningTheFunctionDomain
-(6z+7)+12

We get rid of parentheses

-6z-7+12

We add all the numbers together, and all the variables

-6z+5

Back to the equation:

-(-6z+5)



We get rid of parentheses

6z-5-43=0

We add all the numbers together, and all the variables

6z-48=0

We move all terms containing z to the left, all other terms to the right

6z=48

z=48/6

z=8

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