9-4x=(3+x)/(2)

Solution for 9-4x=(3+x)/(2) equation:

9-4x=(3+x)/(2)

We move all terms to the left:

9-4x-((3+x)/(2))=0

We add all the numbers together, and all the variables

-4x-((x+3)/2)+9=0

We multiply all the terms by the denominator


-4x*2)-((x+3)+9*2)=0

We add all the numbers together, and all the variables

-4x*2)-((x+3)=0

Wy multiply elements

-8x^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-16}=0$