9-4(p+2)+5=2(p-3)-6p+12

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Solution for 9-4(p+2)+5=2(p-3)-6p+12 equation: 



9-4(p+2)+5=2(p-3)-6p+12

We move all terms to the left:

9-4(p+2)+5-(2(p-3)-6p+12)=0

We add all the numbers together, and all the variables

-4(p+2)-(2(p-3)-6p+12)+14=0

We multiply parentheses

-4p-(2(p-3)-6p+12)-8+14=0



We calculate terms in parentheses: -(2(p-3)-6p+12), so:

2(p-3)-6p+12

We add all the numbers together, and all the variables

-6p+2(p-3)+12

We multiply parentheses

-6p+2p-6+12

We add all the numbers together, and all the variables

-4p+6

Back to the equation:

-(-4p+6)



We add all the numbers together, and all the variables

-4p-(-4p+6)+6=0

We get rid of parentheses

-4p+4p-6+6=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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