9-4(6x+5)=6x+3(2x+5)+10

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Solution for 9-4(6x+5)=6x+3(2x+5)+10 equation: 



9-4(6x+5)=6x+3(2x+5)+10

We move all terms to the left:

9-4(6x+5)-(6x+3(2x+5)+10)=0

We multiply parentheses

-24x-(6x+3(2x+5)+10)-20+9=0



We calculate terms in parentheses: -(6x+3(2x+5)+10), so:

6x+3(2x+5)+10

We multiply parentheses

6x+6x+15+10

We add all the numbers together, and all the variables

12x+25

Back to the equation:

-(12x+25)



We add all the numbers together, and all the variables

-24x-(12x+25)-11=0

We get rid of parentheses

-24x-12x-25-11=0

We add all the numbers together, and all the variables

-36x-36=0

We move all terms containing x to the left, all other terms to the right

-36x=36

x=36/-36

x=-1

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