9-2(y+1)=3(y-1)

Solution for 9-2(y+1)=3(y-1) equation:

9-2(y+1)=3(y-1)

We move all terms to the left:

9-2(y+1)-(3(y-1))=0

We multiply parentheses

-2y-(3(y-1))-2+9=0


We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)


We add all the numbers together, and all the variables

-2y-(3y-3)+7=0

We get rid of parentheses

-2y-3y+3+7=0

We add all the numbers together, and all the variables

-5y+10=0

We move all terms containing y to the left, all other terms to the right

-5y=-10

y=-10/-5

y=+2