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9-2(x+4)=3(x+1)-2
We move all terms to the left:
9-2(x+4)-(3(x+1)-2)=0
We multiply parentheses
-2x-(3(x+1)-2)-8+9=0
We calculate terms in parentheses: -(3(x+1)-2), so:We add all the numbers together, and all the variables
3(x+1)-2
We multiply parentheses
3x+3-2
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
-2x-(3x+1)+1=0
We get rid of parentheses
-2x-3x-1+1=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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