9-1/5(4x-12)=x+7

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Solution for 9-1/5(4x-12)=x+7 equation: 



9-1/5(4x-12)=x+7

We move all terms to the left:

9-1/5(4x-12)-(x+7)=0



Domain of the equation: 5(4x-12)!=0

x∈R



We get rid of parentheses

-1/5(4x-12)-x-7+9=0

We multiply all the terms by the denominator


-x*5(4x-12)-7*5(4x-12)+9*5(4x-12)-1=0

Wy multiply elements

-5x^2(4-35x(4+45x(4-1=0

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