9-(t+3)=1+2(t-3)

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Solution for 9-(t+3)=1+2(t-3) equation:



9-(t+3)=1+2(t-3)
We move all terms to the left:
9-(t+3)-(1+2(t-3))=0
We get rid of parentheses
-t-(1+2(t-3))-3+9=0
We calculate terms in parentheses: -(1+2(t-3)), so:
1+2(t-3)
determiningTheFunctionDomain 2(t-3)+1
We multiply parentheses
2t-6+1
We add all the numbers together, and all the variables
2t-5
Back to the equation:
-(2t-5)
We add all the numbers together, and all the variables
-1t-(2t-5)+6=0
We get rid of parentheses
-1t-2t+5+6=0
We add all the numbers together, and all the variables
-3t+11=0
We move all terms containing t to the left, all other terms to the right
-3t=-11
t=-11/-3
t=3+2/3

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