9-(m+5)=3(6m-5)m=1

Solution for 9-(m+5)=3(6m-5)m=1 equation:

9-(m+5)=3(6m-5)m=1

We move all terms to the left:

9-(m+5)-(3(6m-5)m)=0

We get rid of parentheses

-m-(3(6m-5)m)-5+9=0


We calculate terms in parentheses: -(3(6m-5)m), so:

3(6m-5)m

We multiply parentheses

18m^2-15m

Back to the equation:

-(18m^2-15m)


We add all the numbers together, and all the variables

-1m-(18m^2-15m)+4=0

We get rid of parentheses

-18m^2-1m+15m+4=0

We add all the numbers together, and all the variables

-18m^2+14m+4=0

a = -18; b = 14; c = +4;
Δ = b2-4ac
Δ = 142-4·(-18)·4
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-22}{2*-18}=\frac{-36}{-36}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+22}{2*-18}=\frac{8}{-36}
=-2/9
$