9+x-8x2+1=10/2

Solution for 9+x-8x2+1=10/2 equation:

9+x-8x^2+1=10/2

We move all terms to the left:

9+x-8x^2+1-(10/2)=0

We add all the numbers together, and all the variables

-8x^2+x+9+1-5=0

We add all the numbers together, and all the variables

-8x^2+x+5=0

a = -8; b = 1; c = +5;
Δ = b2-4ac
Δ = 12-4·(-8)·5
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*-8}=\frac{-1-\sqrt{161}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*-8}=\frac{-1+\sqrt{161}}{-16}
$