9+8x+4x2=7+10-x

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Solution for 9+8x+4x2=7+10-x equation:



9+8x+4x^2=7+10-x
We move all terms to the left:
9+8x+4x^2-(7+10-x)=0
We add all the numbers together, and all the variables
4x^2+8x-(-1x+17)+9=0
We get rid of parentheses
4x^2+8x+1x-17+9=0
We add all the numbers together, and all the variables
4x^2+9x-8=0
a = 4; b = 9; c = -8;
Δ = b2-4ac
Δ = 92-4·4·(-8)
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{209}}{2*4}=\frac{-9-\sqrt{209}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{209}}{2*4}=\frac{-9+\sqrt{209}}{8} $

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