9+5x+1=1/2(2x+10)+x

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Solution for 9+5x+1=1/2(2x+10)+x equation: 



9+5x+1=1/2(2x+10)+x

We move all terms to the left:

9+5x+1-(1/2(2x+10)+x)=0



Domain of the equation: 2(2x+10)+x)!=0

x∈R



We add all the numbers together, and all the variables

5x-(1/2(2x+10)+x)+10=0

We multiply all the terms by the denominator


5x*2(2x+10)+x)-(1+10*2(2x+10)+x)=0

Wy multiply elements

10x^2(2+x)-(1+20x(2+x)=0



We calculate terms in parentheses: -(1+20x(2+x), so:

1+20x(2+x

determiningTheFunctionDomain
20x(2+x+1

Back to the equation:

-(20x(2+x+1)



We add all the numbers together, and all the variables

10x^2(x+2)-(20x(x+3)=0



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