9+5(x-8)=7(x-4)-3x

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Solution for 9+5(x-8)=7(x-4)-3x equation: 



9+5(x-8)=7(x-4)-3x

We move all terms to the left:

9+5(x-8)-(7(x-4)-3x)=0

We multiply parentheses

5x-(7(x-4)-3x)-40+9=0



We calculate terms in parentheses: -(7(x-4)-3x), so:

7(x-4)-3x

We add all the numbers together, and all the variables

-3x+7(x-4)

We multiply parentheses

-3x+7x-28

We add all the numbers together, and all the variables

4x-28

Back to the equation:

-(4x-28)



We add all the numbers together, and all the variables

5x-(4x-28)-31=0

We get rid of parentheses

5x-4x+28-31=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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