9+5(2v-3)=-2(4v-3)+2v

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Solution for 9+5(2v-3)=-2(4v-3)+2v equation: 



9+5(2v-3)=-2(4v-3)+2v

We move all terms to the left:

9+5(2v-3)-(-2(4v-3)+2v)=0

We multiply parentheses

10v-(-2(4v-3)+2v)-15+9=0



We calculate terms in parentheses: -(-2(4v-3)+2v), so:

-2(4v-3)+2v

We add all the numbers together, and all the variables

2v-2(4v-3)

We multiply parentheses

2v-8v+6

We add all the numbers together, and all the variables

-6v+6

Back to the equation:

-(-6v+6)



We add all the numbers together, and all the variables

10v-(-6v+6)-6=0

We get rid of parentheses

10v+6v-6-6=0

We add all the numbers together, and all the variables

16v-12=0

We move all terms containing v to the left, all other terms to the right

16v=12

v=12/16

v=3/4

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