9+4(2y-3)=-3(5y-5)+8y

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Solution for 9+4(2y-3)=-3(5y-5)+8y equation: 



9+4(2y-3)=-3(5y-5)+8y

We move all terms to the left:

9+4(2y-3)-(-3(5y-5)+8y)=0

We multiply parentheses

8y-(-3(5y-5)+8y)-12+9=0



We calculate terms in parentheses: -(-3(5y-5)+8y), so:

-3(5y-5)+8y

We add all the numbers together, and all the variables

8y-3(5y-5)

We multiply parentheses

8y-15y+15

We add all the numbers together, and all the variables

-7y+15

Back to the equation:

-(-7y+15)



We add all the numbers together, and all the variables

8y-(-7y+15)-3=0

We get rid of parentheses

8y+7y-15-3=0

We add all the numbers together, and all the variables

15y-18=0

We move all terms containing y to the left, all other terms to the right

15y=18

y=18/15

y=1+1/5

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