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9+3x=3(2+x)+3
We move all terms to the left:
9+3x-(3(2+x)+3)=0
We add all the numbers together, and all the variables
3x-(3(x+2)+3)+9=0
We calculate terms in parentheses: -(3(x+2)+3), so:We get rid of parentheses
3(x+2)+3
We multiply parentheses
3x+6+3
We add all the numbers together, and all the variables
3x+9
Back to the equation:
-(3x+9)
3x-3x-9+9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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