9+3b+(b-1)=67

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Solution for 9+3b+(b-1)=67 equation: 



9+3b+(b-1)=67

We move all terms to the left:

9+3b+(b-1)-(67)=0

We add all the numbers together, and all the variables

3b+(b-1)-58=0

We get rid of parentheses

3b+b-1-58=0

We add all the numbers together, and all the variables

4b-59=0

We move all terms containing b to the left, all other terms to the right

4b=59

b=59/4

b=14+3/4

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