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9+3=12+(v-8/2)
We move all terms to the left:
9+3-(12+(v-8/2))=0
We add all the numbers together, and all the variables
-(12+(v-4))+9+3=0
We add all the numbers together, and all the variables
-(12+(v-4))+12=0
We calculate terms in parentheses: -(12+(v-4)), so:We get rid of parentheses
12+(v-4)
determiningTheFunctionDomain (v-4)+12
We get rid of parentheses
v-4+12
We add all the numbers together, and all the variables
v+8
Back to the equation:
-(v+8)
-v-8+12=0
We add all the numbers together, and all the variables
-1v+4=0
We move all terms containing v to the left, all other terms to the right
-v=-4
v=-4/-1
v=+4
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